In the figure,two blocks M and m are tied tog | vedclass

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(D) When the elevator accelerates downwards with an acceleration $a = g$,the effective gravitational field inside the elevator becomes $g_{eff} = g -

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

(D) When the elevator accelerates downwards with an acceleration $a = g$,the effective gravitational field inside the elevator becomes $g_{eff} = g - a = g - g = 0$.Since the effective gravity is zero,the normal force $N$ on block $M$ becomes $M 	imes g_{eff} = 0$.Consequently,the limiting friction $f_{max} = \mu N$ also becomes zero.Since there is no effective weight acting on block $m$ $(m 	imes g_{eff} = 0)$,there is no force to pull the string.Therefore,the tension $T$ in the string becomes zero.Since the effective weight and tension are zero,the blocks do not experience any net force relative to the elevator,so they remain stationary with respect to the elevator.Also,with respect to the ground,both blocks are in free fall,accelerating downwards with $g$.Thus,all the given statements are correct.

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