In the given LCR circuit,the voltage across t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a series $LCR$ circuit,the total voltage $V$ is given by $V = \sqrt{V_R^2 + (V_L - V_C)^2}$.Given: $V = 100\ V$,$V_L = 400\ V$,$V_C = 400\ V$,a

Vedclass · Accepted Answer

$100\ V$,$2\ A$

Vedclass · Answer

(C) In a series $LCR$ circuit,the total voltage $V$ is given by $V = \sqrt{V_R^2 + (V_L - V_C)^2}$.Given: $V = 100\ V$,$V_L = 400\ V$,$V_C = 400\ V$,and $R = 50\ \Omega$.Substituting the values into the formula: $100 = \sqrt{V_R^2 + (400 - 400)^2}$.$100 = \sqrt{V_R^2 + 0^2} = V_R$.So,the voltage across the resistor $V_R = 100\ V$.The current $I$ in the circuit is given by $I = \frac{V_R}{R}$.$I = \frac{100\ V}{50\ \Omega} = 2\ A$.Therefore,the voltage across the resistance is $100\ V$ and the current is $2\ A$.

In the given $LCR$ circuit,the voltage across the terminals of the resistance and the current in the circuit will be:

Similar Questions

Which group of organisms was the first to exist on Earth among the given options?

If $\alpha$ and $\beta$ are the roots of the equation $x^2-2x+4=0$,then $\alpha^9+\beta^9$ is equal to

$A$ body falling from a height of $10\,m$ rebounds from a hard floor. If it loses $20\%$ of its energy on impact,then the coefficient of restitution is:

Three liquids with masses $m_1, m_2, m_3$ are thoroughly mixed. If their specific heats are $c_1, c_2, c_3$ and their temperatures are $T_1, T_2, T_3$ respectively,then the temperature of the mixture is

The value of $\lambda$ such that $\lambda x^2-10 x y+12 y^2+5 x-16 y-3=0$ represents a pair of straight lines is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module