In a hydrogen atom,electrons are excited to t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of spectral lines produced when an electron transitions from an excited state $n_2$ to a lower energy state $n_1$ is given by the formu

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(D) The number of spectral lines produced when an electron transitions from an excited state $n_2$ to a lower energy state $n_1$ is given by the formula: $\frac{(n_2 - n_1)(n_2 - n_1 + 1)}{2}$.Here,the electron is excited to the $5^{th}$ level $(n_2 = 5)$ and returns to the ground state $(n_1 = 1)$.Substituting the values: $\frac{(5 - 1)(5 - 1 + 1)}{2} = \frac{4 	imes 5}{2} = 10$.Therefore,a total of $10$ spectral lines are produced.

In a hydrogen atom,electrons are excited to the $5^{th}$ quantum level. How many different spectral lines may appear in the emission spectrum?

Similar Questions

Which of the following electron transitions in a hydrogen atom will require the largest amount of energy?

The distance between the $4^{th}$ and $3^{rd}$ Bohr orbits of $He^{+}$ is $:-$

The frequency of one of the lines in the Paschen series of a hydrogen atom is $2.340 \times 10^{11} \ Hz$. The quantum number $n_2$ which produces this transition is

When an electron transitions from $n = 4$ to $n = 2$,the emitted spectral line will be ........

Calculate the ratio of the radius of the $2^{nd}$ and $3^{rd}$ orbit of a hydrogen atom. (Note: $r_n \propto n^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module