(D) The numerical aperture $(NA)$ of an optical fibre is given by the formula:$NA = \sqrt{\mu_1^2 - \mu_2^2}$Where $\mu_1$ is the refractive index of

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(D) The numerical aperture $(NA)$ of an optical fibre is given by the formula:$NA = \sqrt{\mu_1^2 - \mu_2^2}$Where $\mu_1$ is the refractive index of the core and $\mu_2$ is the refractive index of the cladding.Given: $\mu_1 = 1.68$,$\mu_2 = 1.44$.Substituting the values:$NA = \sqrt{(1.68)^2 - (1.44)^2}$$NA = \sqrt{2.8224 - 2.0736}$$NA = \sqrt{0.7488}$$NA \approx 0.8653$Therefore,the correct option is $D$.

Class 12 Physics Ray Optics and Optical Instruments Critical Angle and Total Internal Reflection

Medium

In an optical fibre,the refractive index of the inner part (core) is $1.68$ and the refractive index of the outer part (cladding) is $1.44$. The numerical aperture of the fibre is ........

A
$0.5653$
B
$0.6653$
C
$0.7653$
D
$0.8653$

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Ray Optics and Optical Instruments

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Critical Angle and Total Internal Reflection

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In an optical fibre,the refractive index of the inner part (core) is $1.68$ and the refractive index of the outer part (cladding) is $1.44$. The numerical aperture of the fibre is ........

Similar Questions

Explain the use of optical fibre in the medical field.

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