In parallelogram $ABCD$,$AB = 12.5 \, cm$ and $BC = 7 \, cm$,then find the perimeter of $ABCD$ in $cm$.

Can the angles $110^{\circ}, 80^{\circ}, 70^{\circ}$ and $95^{\circ}$ be the angles of a quadrilateral? Why or why not?

The angle between two altitudes of a parallelogram drawn from the vertex of an obtuse angle is $60^{\circ}$. Find the angles of the parallelogram.

In $\Delta PQR$,$X, Y$ and $Z$ are the midpoints of $PQ, QR$ and $RP$ respectively. If $PQ = 7.2 \, cm$,$PR = 8.4 \, cm$ and $XZ = 3.8 \, cm$,then find the perimeter of $\Delta PQR$ and $\Delta XYZ$.

In parallelogram $ABCD$,$\angle A = \angle B - 30^{\circ}$,then find $\angle A$. (in $^{\circ}$)

In a rhombus $ABCD$,if $AB = 13 \text{ cm}$,then the perimeter of $ABCD = \ldots \ldots \ldots \text{ cm}$.