In the above diagram,a strong bar magnet is m | vedclass

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(A) According to Lenz's Law,the induced current in a coil opposes the change in magnetic flux that produces it.For solenoid-$1$: The North pole of the

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$B A$ and $C D$

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(A) According to Lenz's Law,the induced current in a coil opposes the change in magnetic flux that produces it.For solenoid-$1$: The North pole of the magnet is moving away from it. To oppose this,the end $B$ of solenoid-$1$ must act as a South pole. Using the right-hand thumb rule,the current flows from $B$ to $A$.For solenoid-$2$: The South pole of the magnet is approaching it. To oppose this,the end $C$ of solenoid-$2$ must act as a South pole. Using the right-hand thumb rule,the current flows from $C$ to $D$.Therefore,the directions of induced current are $B A$ and $C D$ respectively.

In the above diagram,a strong bar magnet is moving towards solenoid-$2$ from solenoid-$1$. The direction of induced current in solenoid-$1$ and that in solenoid-$2$,respectively,are through the directions:

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