In the reaction shown,5 g of toluene is conv | vedclass

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(D) The molar mass of toluene $(C_7H_8)$ is $7 	imes 12 + 8 	imes 1 = 92 \ g/mol$.Number of moles of toluene = $\frac{5 \ g}{92 \ g/mol} = \frac{5}{

Vedclass · Accepted Answer

$530$

Vedclass · Answer

(D) The molar mass of toluene $(C_7H_8)$ is $7 	imes 12 + 8 	imes 1 = 92 \ g/mol$.Number of moles of toluene = $\frac{5 \ g}{92 \ g/mol} = \frac{5}{92} \ mol$.Since the reaction stoichiometry is $1:1$,the theoretical moles of benzaldehyde produced would be $\frac{5}{92} \ mol$.Given the yield is $92 \%$,the actual moles of benzaldehyde produced = $\frac{5}{92} 	imes \frac{92}{100} = 5 	imes 10^{-2} \ mol$.The molar mass of benzaldehyde $(C_7H_6O)$ is $7 	imes 12 + 6 	imes 1 + 16 = 106 \ g/mol$.Mass of benzaldehyde produced = $	ext{moles} 	imes 	ext{molar mass} = (5 	imes 10^{-2} \ mol) 	imes (106 \ g/mol) = 530 	imes 10^{-2} \ g$.Thus,the value is $530$.

In the reaction shown,$5 \ g$ of toluene is converted into benzaldehyde with $92 \%$ yield. The amount of benzaldehyde produced is $.... \times 10^{-2} \ g$. (Nearest integer)

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