In the above reaction,'X' stands for: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given reaction is the reduction of nitrobenzene to aniline using a metal-acid reducing agent $(Sn + HCl)$.Nitrobenzene $(C_6H_5NO_2)$ reacts w

Vedclass · Accepted Answer

$NH_2$

Vedclass · Answer

(A) The given reaction is the reduction of nitrobenzene to aniline using a metal-acid reducing agent $(Sn + HCl)$.Nitrobenzene $(C_6H_5NO_2)$ reacts with $6[H]$ provided by the $Sn + HCl$ mixture to form aniline $(C_6H_5NH_2)$ and water $(2H_2O)$.The reaction is: $C_6H_5NO_2 + 6[H] \xrightarrow{Sn/HCl} C_6H_5NH_2 + 2H_2O$.Comparing this with the given reaction,'$X$' corresponds to the $-NH_2$ group.Therefore,the correct option is $(A)$.

In the above reaction,'$X$' stands for:

Similar Questions

Identify the product obtained when nitroethane is treated with $Sn/HCl$ under ideal conditions.

$CH_3-CH_2-I$ $\xrightarrow{NaCN} A$ $\xrightarrow[Partial \ hydrolysis]{\Theta OH} B$ $\xrightarrow[Br_2]{NaOH} C$. Product $C$ is

What are $X$ and $Y$ respectively in the following reactions?

Which of the following compounds can be reduced to form a primary amine?

The product of the reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module