In the adjacent figure,find the area of the s | vedclass

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(C) The rectangle is inscribed in the circle. The diagonal of the rectangle is equal to the diameter of the circle.Diagonal of the rectangle $= \sqrt{

Vedclass · Accepted Answer

$30.57$

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(C) The rectangle is inscribed in the circle. The diagonal of the rectangle is equal to the diameter of the circle.Diagonal of the rectangle $= \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \ cm$.Therefore,the diameter of the circle $= 10 \ cm$,and the radius $r = 10/2 = 5 \ cm$.Area of the circle $= \pi r^2 = (22/7) 	imes 5 	imes 5 = 550/7 \approx 78.57 \ cm^2$.Area of the rectangle $= 	ext{length} 	imes 	ext{breadth} = 8 	imes 6 = 48 \ cm^2$.Area of the shaded region $= 	ext{Area of the circle} - 	ext{Area of the rectangle} = 78.57 - 48 = 30.57 \ cm^2$.

In the adjacent figure,find the area of the shaded region in $cm^2$. (Use $\pi = 22/7$)

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