In the Cannizzaro reaction given below,the sl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The mechanism of the Cannizzaro reaction involves the following steps: $1$. Nucleophilic attack of $\stackrel{\ominus}{O}H$ on the carbonyl carbon

Vedclass · Accepted Answer

The transfer of hydride ion to carbonyl group

Vedclass · Answer

(B) The mechanism of the Cannizzaro reaction involves the following steps: $1$. Nucleophilic attack of $\stackrel{\ominus}{O}H$ on the carbonyl carbon of one molecule of benzaldehyde to form a dihydroxyalkoxide intermediate. $2$. The hydride ion $(H^{\ominus})$ transfer from the dihydroxyalkoxide intermediate to the carbonyl carbon of another molecule of benzaldehyde. This is the rate-determining step (slowest step) because it involves the breaking of a $C-H$ bond. $3$. Rapid proton exchange between the resulting carboxylic acid and the alkoxide ion to form the carboxylate ion and alcohol.

In the Cannizzaro reaction given below,the slowest step is $:-$
$2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$

Similar Questions

$3$-hydroxybutanal is formed when $(X)$ reacts with $(Y)$ in a dilute $(Z)$ solution. What are $X, Y$ and $Z$?

In the given conversion,the best yield will be obtained with:

$C_7H_6O$ is the molecular formula of $X$,which gives a negative Fehling test but a positive Tollen's test. $X$ $\xrightarrow[AcONa]{Ac_2O} Y$ $\xrightarrow[Me_2NH]{1. SOCl_2} Z$. The correct option is:

In the given reaction $C_6H_5CHO + X \xrightarrow{(i) Zn, (ii) HOH/NH_4Cl} C_6H_5-CH(OH)-CH_2-COOC_2H_5$,$[X]$ will be:

Which of the following compounds undergoes the Cannizzaro reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the Cannizzaro reaction given below,the slowest step is $:-$ $2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$