In the case of a common emitter transistor amplifier,the ratio of collector current to emitter current is $0.96$. Then,the current gain $(\beta)$ of the amplifier is:

  • A
    $6$
  • B
    $48$
  • C
    $24$
  • D
    $12$

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In a transistor, if $\frac{I_C}{I_E} = \alpha$ and $\frac{I_C}{I_B} = \beta$. If $\alpha$ varies between $\frac{20}{21}$ and $\frac{100}{101}$, then the value of $\beta$ lies between:

In the circuit shown in the figure,when the input voltage $V_i$ is $10\, V$,$V_{BE}$ is zero and $V_{CE}$ is also zero. Find the values of $I_B$,$I_C$,and $\beta$.

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What is the voltage gain in a common emitter amplifier,where input resistance is $3 \, \Omega$ and load resistance is $24 \, \Omega$,and the current gain $\beta = 0.6$?

In a transistor, comparing the doping of emitter, base, and collector, the part which is heavily doped and that which is lightly doped are respectively:

$A$ transistor is used in common emitter mode as an amplifier. Then:

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