In the $CB$ mode of a transistor, when the collector voltage is changed by $0.5\,V$, the collector current changes by $0.05\,mA$. The output resistance will be....$k\Omega$.

In the study of a transistor as an amplifier,if $\alpha = \frac{I_C}{I_E} = 0.98$ and $\beta = \frac{I_C}{I_B} = 49$,where $I_C, I_B,$ and $I_E$ are collector,base,and emitter currents respectively,then $\left(\frac{1}{\alpha} - \frac{1}{\beta}\right)$ is equal to:

If a transistor having $\alpha = 0.9$ is used in $CE$ configuration, then for a change of $0.4 \text{ mA}$ in base current, what will be the change in collector current (in $\text{ mA}$)?

In a common emitter transistor amplifier, an input signal of $10 \ mV$ is applied. Due to this signal, the change in base current is $50 \ \mu A$ and the corresponding change in collector current is $5 \ mA$. If the load resistance in the collector-emitter circuit is $5 \ k\Omega$, the change in output voltage will be ..... $V$.

In a junction transistor, the collector current changes by $6.8 \,mA$, if the emitter current is changed by $7 \,mA$. For such a transistor, the current amplification factor is

Three terminals of a transistor,denoted by $P, Q,$ and $R,$ are tested using a multimeter. No conduction occurs between $P$ and $Q.$ When the negative lead of the multimeter is connected to $R$ and the positive lead is connected to either $P$ or $Q,$ the meter shows some resistance. Which of the following options is correct for the given transistor?