In the circuit shown, when the current i is 3 | vedclass

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(A) Let the potential difference between $A$ and $B$ be $V_{AB}$. The circuit consists of a resistor $R$ and an inductor $L$ in series.The potential d

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$3$

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(A) Let the potential difference between $A$ and $B$ be $V_{AB}$. The circuit consists of a resistor $R$ and an inductor $L$ in series.The potential difference across the circuit is given by $V_{AB} = iR + L(di/dt)$.Case $1$: $i = 3 	ext{ A}$, $di/dt = 1 	ext{ A/s}$, $V_{AB} = 12 	ext{ V}$.$12 = 3R + L(1) \implies 3R + L = 12$  --- $(1)$Case $2$: $i = 3 	ext{ A}$, $di/dt = -1 	ext{ A/s}$, $V_{AB} = 6 	ext{ V}$.$6 = 3R + L(-1) \implies 3R - L = 6$  --- $(2)$Adding equations $(1)$ and $(2)$:$(3R + L) + (3R - L) = 12 + 6$$6R = 18$$R = 3 	ext{ } \Omega$.

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