In the circuit shown below,the ammeter readin | vedclass

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Question

(B) Since the ammeter reading is zero,no current flows through the right branch of the circuit. Let $i_1$ be the current flowing through the left loop

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(B) Since the ammeter reading is zero,no current flows through the right branch of the circuit. Let $i_1$ be the current flowing through the left loop. Applying Kirchhoff's voltage law to the left loop: $12 - 500 i_1 - R i_1 = 0$  --- $(i)$ Since the ammeter reading is zero,the potential difference across the resistor $R$ must be equal to the electromotive force of the battery in the right branch. Thus,the voltage across $R$ is $V_R = R i_1 = 2 	ext{ V}$. Substituting $R i_1 = 2$ into equation $(i)$: $12 - 500 i_1 - 2 = 0$ $10 = 500 i_1$ $i_1 = \frac{10}{500} = \frac{1}{50} 	ext{ A}$. Now,using $R i_1 = 2$: $R 	imes \frac{1}{50} = 2$ $R = 100 \Omega$.

In the circuit shown below,the ammeter reading is zero. Then the value of the resistance $R$ is (in $\Omega$)

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