The de-Broglie wavelength of an electron havi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Kinetic energy,$KE = 80 eV = 80 	imes 1.6 	imes 10^{-19} J = 128 	imes 10^{-19} J$.De-Broglie wavelength is given by $\lambda = \frac{h}{\sqrt{

Vedclass · Accepted Answer

$1.4$

Vedclass · Answer

(D) Kinetic energy,$KE = 80 eV = 80 	imes 1.6 	imes 10^{-19} J = 128 	imes 10^{-19} J$.De-Broglie wavelength is given by $\lambda = \frac{h}{\sqrt{2m(KE)}}$.Substituting the values:$\lambda = \frac{6.6 	imes 10^{-34}}{\sqrt{2 	imes 9 	imes 10^{-31} 	imes 128 	imes 10^{-19}}}$$\lambda = \frac{6.6 	imes 10^{-34}}{\sqrt{256 	imes 9 	imes 10^{-50}}}$$\lambda = \frac{6.6 	imes 10^{-34}}{16 	imes 3 	imes 10^{-25}}$$\lambda = \frac{6.6}{48} 	imes 10^{-9} m = 0.1375 	imes 10^{-9} m = 1.375 	imes 10^{-10} m$.Since $1 	ext{ Å} = 10^{-10} m$,we get $\lambda \approx 1.4 	ext{ Å}$.

The de-Broglie wavelength of an electron having $80 eV$ energy is nearly ($1 eV = 1.6 \times 10^{-19} J$,Mass of the electron $= 9 \times 10^{-31} kg$,Planck's constant $= 6.6 \times 10^{-34} J-s$) (in $\text{ Å}$)

Similar Questions

$2\,g$ of steam condenses when passed through $40\,g$ of water initially at $25\,^{\circ}C$. The condensation of steam raises the temperature of water to $54.3\,^{\circ}C$. What is the latent heat of steam in $cal/g$?

One of the parents of a cross has a mutation in its mitochondria. In that cross,that parent is taken as a male. During segregation of $F_{2}$-progenies,that mutation is found in:

Where is the pacemaker located?

What is the stored food (nutrient) in algae?

$A$ gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24 \ L$ of this mixture at $NTP$ is ............ $g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module