In the circuit shown in the adjoining figure, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The circuit represents a Wheatstone bridge where the current between $B$ and $D$ is zero,implying the bridge is balanced.In the given circuit,the

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) The circuit represents a Wheatstone bridge where the current between $B$ and $D$ is zero,implying the bridge is balanced.In the given circuit,the arms are:$AB = 12 \, \Omega + 4 \, \Omega = 16 \, \Omega$$BC = X \, \Omega$$AD = 1 \, \Omega + 3 \, \Omega = 4 \, \Omega$$DC = 1 \, \Omega \parallel 1 \, \Omega = \frac{1 	imes 1}{1 + 1} = 0.5 \, \Omega$For a balanced Wheatstone bridge,the ratio of resistances in opposite arms must be equal:$\frac{AB}{AD} = \frac{BC}{DC}$$\frac{16}{4} = \frac{X}{0.5}$$4 = \frac{X}{0.5}$$X = 4 	imes 0.5 = 2 \, \Omega$

In the circuit shown in the adjoining figure,the current between $B$ and $D$ is zero. The unknown resistance $X$ is ................ $\Omega$.

Similar Questions

In the circuit shown in the figure,if no current flows through the galvanometer when the key $K$ is closed,the bridge is balanced. The balancing condition for the bridge is

Kirchhoff's first law,$i.e.$,$\Sigma i = 0$ at a junction,is based on the law of conservation of:

In a balanced Wheatstone's network,the resistances in the arms $Q$ and $S$ are interchanged. As a result of this:

For the circuit shown in the figure,the current $I$ will be .......$A$.

The figure shows a circuit diagram of a 'Wheatstone Bridge' to measure the resistance $G$ of the galvanometer. The relation $\frac{P}{Q} = \frac{R}{G}$ will be satisfied only when

Vedclass Test Series

Exam Paper Generator

Online Exam Module