In the circuit shown in the figure,C = 6,mu F | vedclass

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(C) The two capacitors $C$ and $2C$ are connected in series with a $10\,V$ $DC$ source.In a series combination,the equivalent capacitance $C_{eq}$ is

Vedclass · Accepted Answer

$40$

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(C) The two capacitors $C$ and $2C$ are connected in series with a $10\,V$ $DC$ source.In a series combination,the equivalent capacitance $C_{eq}$ is given by $\frac{1}{C_{eq}} = \frac{1}{C} + \frac{1}{2C} = \frac{2+1}{2C} = \frac{3}{2C}$.Therefore,$C_{eq} = \frac{2C}{3}$.The total charge $Q$ supplied by the battery is $Q = C_{eq} 	imes V = \frac{2C}{3} 	imes 10 = \frac{20C}{3}$.Given $C = 6\,\mu F$,the charge $Q = \frac{20 	imes 6}{3} = 40\,\mu C$.Since the capacitors are in series,the same charge $Q$ is stored in both capacitors.

In the circuit shown in the figure,$C = 6\,\mu F$. The charge stored in the capacitor of capacity $C$ is..........$\mu C$.

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