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(C) An ideal diode in forward bias acts as a short circuit (zero resistance), and in reverse bias, it acts as an open circuit (infinite resistance).Ca

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$1/2$

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(C) An ideal diode in forward bias acts as a short circuit (zero resistance), and in reverse bias, it acts as an open circuit (infinite resistance).Case $1$: Diode $D$ is forward biased.The upper branch has a resistance of $30 \ \Omega$ in series with the diode (which acts as $0 \ \Omega$). The lower branch has a resistance of $30 \ \Omega$. These two branches are in parallel.$R_1 = (30 \ \Omega \parallel 30 \ \Omega) = \frac{30 	imes 30}{30 + 30} = \frac{900}{60} = 15 \ \Omega$.Case $2$: Diode $D$ is reverse biased.The upper branch acts as an open circuit (infinite resistance). Thus, only the lower branch with $30 \ \Omega$ resistance is connected between $A$ and $B$.$R_2 = 30 \ \Omega$.Ratio $R_1/R_2 = 15/30 = 1/2$.

In the diagram shown, the resistance between points $A$ and $B$ is '$R_1$' when an ideal diode $D$ is forward biased and is '$R_2$' when ideal diode $D$ is reverse biased. The ratio $R_1/R_2$ is

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