In the figure given below,the current passing | vedclass

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(B) The two resistors $6\,\Omega$ and $4\,\Omega$ are connected in parallel.Let $I = 1.2\,A$ be the total current entering the parallel combination.Us

Vedclass · Accepted Answer

$0.48$

Vedclass · Answer

(B) The two resistors $6\,\Omega$ and $4\,\Omega$ are connected in parallel.Let $I = 1.2\,A$ be the total current entering the parallel combination.Using the current divider rule,the current $I_1$ passing through the $6\,\Omega$ resistor is given by:$I_1 = I 	imes \left( \frac{R_2}{R_1 + R_2} ight)$Here,$R_1 = 6\,\Omega$ and $R_2 = 4\,\Omega$.$I_1 = 1.2 	imes \left( \frac{4}{6 + 4} ight)$$I_1 = 1.2 	imes \left( \frac{4}{10} ight)$$I_1 = 1.2 	imes 0.4 = 0.48\,A$.

In the figure given below,the current passing through the $6\,\Omega$ resistor is ........... $A$.

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