The reading of the ideal voltmeter in the adj | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The circuit consists of two batteries of $10\,V$ and $4\,V$ connected in opposition,and two resistors of $10\,\Omega$ and $20\,\Omega$ in series.T

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) The circuit consists of two batteries of $10\,V$ and $4\,V$ connected in opposition,and two resistors of $10\,\Omega$ and $20\,\Omega$ in series.Total electromotive force $(EMF)$ in the circuit is $E_{net} = 10\,V - 4\,V = 6\,V$.Total resistance in the circuit is $R_{total} = 10\,\Omega + 20\,\Omega = 30\,\Omega$.The current flowing in the circuit is $i = \frac{E_{net}}{R_{total}} = \frac{6\,V}{30\,\Omega} = 0.2\,A = \frac{1}{5}\,A$.The voltmeter is connected between points $A$ and $N$. We can calculate the potential difference $V_{AN}$ by traversing the path $A-B-N$.Moving from $A$ to $B$,we pass through the $10\,V$ battery (from positive to negative terminal),so the potential drops by $10\,V$.Moving from $B$ to $N$,we pass through the $10\,\Omega$ resistor in the direction of current,so the potential drops by $iR = (0.2\,A) 	imes (10\,\Omega) = 2\,V$.Thus,$V_A - V_N = 10\,V - 2\,V = 8\,V$.Alternatively,traversing path $A-C-N$: $V_A - V_C = i 	imes (20\,\Omega) = 0.2 	imes 20 = 4\,V$. Moving from $C$ to $N$,we pass through the $4\,V$ battery (from negative to positive terminal),so the potential increases by $4\,V$. Thus,$V_A - V_N = 4\,V + 4\,V = 8\,V$.

The reading of the ideal voltmeter in the adjoining diagram will be ................. $V$.

Similar Questions

$A$ $100\, V$ voltmeter of internal resistance $20\, k\Omega$ in series with a high resistance $R$ is connected to a $110\, V$ line. The voltmeter reads $5\, V$. The value of $R$ is ................ $k\Omega$.

$A$ voltmeter of resistance $150 \Omega$ connected across a cell of e.m.f. $3 \ V$ reads $2.5 \ V$. What is the internal resistance of the cell (in $\Omega$)?

The charge flowing through a resistor $R$ varies with time $t$ as $Q = 3t - 6t^2$. The heat produced in $R$ until the current in it becomes zero is:

$A$ battery of $e.m.f.$ $10\, V$ is connected to a resistance network as shown in the figure. The potential difference ${V_A} - {V_B}$ between the points $A$ and $B$ is .................... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module