In the following reaction,X is:X xrightarrow{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction sequence is as follows:$1$. $X$ is Aniline $(C_6H_5NH_2)$.$2$. Bromination of Aniline with $Br_2$ water gives $2,4,6$-Tribromoaniline

Vedclass · Accepted Answer

Aniline

Vedclass · Answer

(D) The reaction sequence is as follows:$1$. $X$ is Aniline $(C_6H_5NH_2)$.$2$. Bromination of Aniline with $Br_2$ water gives $2,4,6$-Tribromoaniline $(Y)$.$3$. Treatment of $Y$ with $NaNO_2 + HCl$ at $0-5 \ ^\circ C$ yields the diazonium salt,$2,4,6$-Tribromobenzenediazonium chloride $(Z)$.$4$. Boiling $Z$ with ethanol $(C_2H_5OH)$ results in the reduction of the diazonium group to a hydrogen atom,producing $1,3,5$-Tribromobenzene.Therefore,$X$ is Aniline.

In the following reaction,$X$ is:
$X$ $\xrightarrow{\text{Bromination}} Y$ $\xrightarrow{NaNO_2 + HCl} Z$ $\xrightarrow[C_2H_5OH]{\text{Boiling}} \text{1,3,5-Tribromobenzene}$

Similar Questions

What is the correct order of increasing basic strength for the bases $NH_3$,$CH_3NH_2$,and $(CH_3)_2NH$?

The reaction sequence is given as follows:
$CH_3-CO-CH_2-CH_2-CO-CH_3$ $\xrightarrow[(NH_4)_2CO_3]{\Delta} (A)$ $\xrightarrow[CCl_3CO_2Na]{\Delta} (B)$
Product $(B)$ of the above reaction is:

Which of the following is the strongest base?

Which among the following compounds has the lowest boiling point?

Identify $X$ and $Y$ in the following reaction: ${C_6H_5NH_2}$ $\xrightarrow[0^{\circ} - 5^{\circ}C]{NaNO_2 + 2HCl} X$ $\xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the following reaction,$X$ is:$X$ $\xrightarrow{\text{Bromination}} Y$ $\xrightarrow{NaNO_2 + HCl} Z$ $\xrightarrow[C_2H_5OH]{\text{Boiling}} \text{1,3,5-Tribromobenzene}$