The reaction sequence is given as follows:CH_ | vedclass

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(A) Step $1$: The reaction of $CH_3-CO-CH_2-CH_2-CO-CH_3$ (hexane$-2,5-$dione) with $(NH_4)_2CO_3$ is a Paal-Knorr pyrrole synthesis,which yields $2,5

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$3-$chloro$-2,6-$dimethylpyridine

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(A) Step $1$: The reaction of $CH_3-CO-CH_2-CH_2-CO-CH_3$ (hexane$-2,5-$dione) with $(NH_4)_2CO_3$ is a Paal-Knorr pyrrole synthesis,which yields $2,5-$dimethylpyrrole as product $(A)$.Step $2$: The reaction of $2,5-$dimethylpyrrole with $CCl_3CO_2Na$ (sodium trichloroacetate) under heating is an abnormal Reimer-Tiemann reaction. This reaction involves the insertion of a dichlorocarbene $(:CCl_2)$ species into the pyrrole ring,followed by ring expansion to form a pyridine derivative.Step $3$: The product $(B)$ formed is $3-$chloro$-2,6-$dimethylpyridine.

The reaction sequence is given as follows:
$CH_3-CO-CH_2-CH_2-CO-CH_3$ $\xrightarrow[(NH_4)_2CO_3]{\Delta} (A)$ $\xrightarrow[CCl_3CO_2Na]{\Delta} (B)$
Product $(B)$ of the above reaction is:

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The reaction sequence is given as follows:$CH_3-CO-CH_2-CH_2-CO-CH_3$ $\xrightarrow[(NH_4)_2CO_3]{\Delta} (A)$ $\xrightarrow[CCl_3CO_2Na]{\Delta} (B)$Product $(B)$ of the above reaction is: