In the following reaction sequence,CH_3-CHO x | vedclass

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(C) In the first step,acetaldehyde $(CH_3-CHO)$ reacts with chlorine $(Cl_2)$ and calcium hydroxide $(Ca(OH)_2)$ to undergo the haloform reaction,prod

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$C_6H_5-NC$

Vedclass · Answer

(C) In the first step,acetaldehyde $(CH_3-CHO)$ reacts with chlorine $(Cl_2)$ and calcium hydroxide $(Ca(OH)_2)$ to undergo the haloform reaction,producing chloroform $(CHCl_3)$.$2CH_3-CHO + 3Cl_2 + Ca(OH)_2 \rightarrow CHCl_3 + (HCOO)_2Ca + 2H_2O$ (Note: The reaction produces $CHCl_3$ as the haloform).In the second step,chloroform $(CHCl_3)$ reacts with aniline $(C_6H_5-NH_2)$ and alcoholic $KOH$ (Carbylamine reaction) to form phenyl isocyanide $(C_6H_5-NC)$.$C_6H_5-NH_2 + CHCl_3 + 3KOH \xrightarrow{\Delta} C_6H_5-NC + 3KCl + 3H_2O$

In the following reaction sequence,$CH_3-CHO$ $\xrightarrow{Cl_2 / Ca(OH)_2} X$ $\xrightarrow{C_6H_5-NH_2 / \text{Alc. KOH}} Y$. $Y$ is:

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