In the following reaction sequence,the compound $J$ is an intermediate.
$I$ $\xrightarrow{(CH_3CO)_2O / CH_3COONa} J$ $\xrightarrow[(ii) \text{ anhyd. } AlCl_3]{(i) H_2, Pd/C, (ii) SOCl_2} K$
$J \left( C_9H_8O_2 \right)$ gives effervescence on treatment with $NaHCO_3$ and positive Baeyer's test.
$1.$ The compound $K$ is
$2.$ The compound $I$ is
Give the answer for question $1$ and $2.$

  • A
    $(B, D)$
  • B
    $(B, C)$
  • C
    $(C, A)$
  • D
    $(A, D)$

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Which of the following has highly acidic hydrogen?

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$(b)$ $CH_3COCH_2COCH_3$
$(c)$ $C_2H_5OOCCH_2COOC_2H_5$
decreases as:

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Amongst the following, the total number of compounds soluble in aqueous $NaOH$ at room temperature is:
$(I)$ Benzaldehyde
$(II)$ $1$-Naphthol
$(III)$ $4$-(Dimethylamino)phenol
$(IV)$ $4$-Methylphenol
$(V)$ Benzoic acid
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$(VIII)$ $1,4$-Di-tert-butylbenzene
$(IX)$ $1$-Naphthylmethanol

In the given reaction $[X]$ will be :

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