The acid strength of the active methylene gro | vedclass

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(A) The acidity of an active methylene group depends on the electron-withdrawing power of the adjacent functional groups ($E_1$ and $E_2$).These group

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$b > a > c$

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(A) The acidity of an active methylene group depends on the electron-withdrawing power of the adjacent functional groups ($E_1$ and $E_2$).These groups stabilize the resulting carbanion through resonance and the inductive effect.Ketone groups $(-COCH_3)$ are more electron-withdrawing than ester groups $(-COOC_2H_5)$ because the oxygen atom in the ester group donates electrons via resonance ($-OR$ group),which reduces its electron-withdrawing ability compared to a ketone.Comparing the compounds:$(b)$ $CH_3COCH_2COCH_3$: Has two ketone groups. The carbanion is highly stabilized by two strong electron-withdrawing groups.$(a)$ $CH_3COCH_2COOC_2H_5$: Has one ketone and one ester group. The carbanion is less stabilized than in $(b)$.$(c)$ $C_2H_5OOCCH_2COOC_2H_5$: Has two ester groups. The carbanion is the least stabilized among the three.Thus,the order of acid strength is $b > a > c$.

The acid strength of the active methylene group in
$(a)$ $CH_3COCH_2COOC_2H_5$
$(b)$ $CH_3COCH_2COCH_3$
$(c)$ $C_2H_5OOCCH_2COOC_2H_5$
decreases as:

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The acid strength of the active methylene group in$(a)$ $CH_3COCH_2COOC_2H_5$$(b)$ $CH_3COCH_2COCH_3$$(c)$ $C_2H_5OOCCH_2COOC_2H_5$decreases as: