In the following sequence of reactions:C_6H_5 | vedclass

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(B) Step $1$: Toluene $(C_6H_5CH_3)$ undergoes oxidation with $KMnO_4$ to form benzoic acid $(C_6H_5COOH)$,which is product $A$.Step $2$: Benzoic acid

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$C_6H_5CHO$

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(B) Step $1$: Toluene $(C_6H_5CH_3)$ undergoes oxidation with $KMnO_4$ to form benzoic acid $(C_6H_5COOH)$,which is product $A$.Step $2$: Benzoic acid reacts with thionyl chloride $(SOCl_2)$ to form benzoyl chloride $(C_6H_5COCl)$,which is product $B$.Step $3$: Benzoyl chloride undergoes Rosenmund reduction with $H_2/Pd$ and $BaSO_4$ to form benzaldehyde $(C_6H_5CHO)$,which is product $C$.

In the following sequence of reactions:
$C_6H_5CH_3$ $\xrightarrow{KMnO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{H_2/Pd, BaSO_4} C$
the product $C$ is:

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In the following sequence of reactions:$C_6H_5CH_3$ $\xrightarrow{KMnO_4} A$ $\xrightarrow{SOCl_2} B$ $\xrightarrow{H_2/Pd, BaSO_4} C$the product $C$ is: