In the given circuit,the potential difference | vedclass

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(A) The circuit consists of a $5 \mu F$ capacitor in series with a parallel combination of three capacitors $(4 \mu F, 8 \mu F, 4 \mu F)$.First,calcul

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(A) The circuit consists of a $5 \mu F$ capacitor in series with a parallel combination of three capacitors $(4 \mu F, 8 \mu F, 4 \mu F)$.First,calculate the equivalent capacitance of the parallel combination $(C_p)$:$C_p = 4 \mu F + 8 \mu F + 4 \mu F = 16 \mu F$.Now,the circuit is a series combination of $C_1 = 5 \mu F$ and $C_p = 16 \mu F$ connected to a $63 V$ source.The potential difference across the $5 \mu F$ capacitor $(V_1)$ is given by the voltage divider rule for capacitors:$V_1 = \left( \frac{C_p}{C_1 + C_p} ight) V_{total}$$V_1 = \left( \frac{16}{5 + 16} ight) 	imes 63 V$$V_1 = \left( \frac{16}{21} ight) 	imes 63 V = 16 	imes 3 V = 48 V$.

In the given circuit,the potential difference across the $5 \mu F$ capacitor is: (in $V$)

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