Three plates of common surface area A are con | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given circuit consists of three plates. Let the middle plate be connected to terminal $A$ and the top and bottom plates be connected together

Vedclass · Accepted Answer

$\frac{2\varepsilon_0 A}{d}$

Vedclass · Answer

(D) The given circuit consists of three plates. Let the middle plate be connected to terminal $A$ and the top and bottom plates be connected together to terminal $B$.This arrangement forms two capacitors in parallel,each formed by the middle plate and one of the outer plates.The capacitance of each capacitor is $C = \frac{\varepsilon_0 A}{d}$.Since the two capacitors are in parallel,the effective capacitance is $C_{eq} = C + C = 2C$.Substituting the value of $C$,we get $C_{eq} = \frac{2\varepsilon_0 A}{d}$.

Three plates of common surface area $A$ are connected as shown. The effective capacitance will be

Similar Questions

Two capacitors each of capacity $2\,\mu F$ are connected in parallel. This system is connected in series with a third capacitor of $12\,\mu F$ capacity. The equivalent capacity of the system will be......$\mu F$

What is the equivalent capacitance between $A$ and $B$?

Three capacitors each of $4\,\mu F$ are to be connected in such a way that the effective capacitance is $6\,\mu F$. This can be done by connecting them:

Find the equivalent capacitance between $A$ and $B$. (in $C$)

In the circuit shown,the energy stored in the $1 \ \mu F$ capacitor is ...... $\mu J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module