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(B) In an $LCR$ series circuit,the voltage across the inductor is $V_L$ (reading of $V_1$) and across the capacitor is $V_C$ (reading of $V_2$).Given

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$220 \, V, 2.2 \, A$

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(B) In an $LCR$ series circuit,the voltage across the inductor is $V_L$ (reading of $V_1$) and across the capacitor is $V_C$ (reading of $V_2$).Given $V_1 = V_L = 300 \, V$ and $V_2 = V_C = 300 \, V$.Since $V_L = V_C$,the circuit is in a state of electrical resonance.At resonance,the net impedance $Z$ of the circuit is equal to the resistance $R$,so $Z = R = 100 \, \Omega$.The total voltage applied is $V = 220 \, V$.The current $I$ in the circuit is given by $I = \frac{V}{Z} = \frac{220 \, V}{100 \, \Omega} = 2.2 \, A$.This is the reading of the ammeter $A$.At resonance,the total voltage $V$ is equal to the voltage across the resistor $V_R$ (reading of $V_3$).Therefore,$V_3 = V_R = V = 220 \, V$.Thus,the reading of $V_3$ is $220 \, V$ and the reading of $A$ is $2.2 \, A$.

In the given circuit,the readings of voltmeters $V_1$ and $V_2$ are $300 \, V$ each. The readings of voltmeter $V_3$ and ammeter $A$ are respectively:

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