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(B) The circuit consists of two branches feeding into a $NOR$ gate. Each branch has a $NAND$ gate followed by a $NOT$ gate (which together form an $AN

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$0$,$1$

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(B) The circuit consists of two branches feeding into a $NOR$ gate. Each branch has a $NAND$ gate followed by a $NOT$ gate (which together form an $AND$ gate). Let the output of the top branch be $Y_1$. The top branch has inputs $A$ and $B$ to a $NAND$ gate,followed by a $NOT$ gate. This is equivalent to an $AND$ gate. So,$Y_1 = A \cdot B = 1 \cdot 0 = 0$. Similarly,the bottom branch has inputs $A$ and $B$ to a $NAND$ gate,followed by a $NOT$ gate. This is also equivalent to an $AND$ gate. So,the output of the bottom branch is $A \cdot B = 1 \cdot 0 = 0$. Now,$Y_1$ is the output of the top branch,so $Y_1 = 0$. The final gate is a $NOR$ gate with both inputs as $0$. The output $Y_2$ of a $NOR$ gate is given by $\overline{0 + 0} = \overline{0} = 1$. Thus,$Y_1 = 0$ and $Y_2 = 1$.

In the given logic circuit,$A=1$ and $B=0$. The values of $Y_1$ and $Y_2$ are respectively:

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