In the ground state of atomic Fe ,(Z = 26),th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $Fe$ $(Z = 26)$ is $[Ar] 3d^6 4s^2$.In the $3d$ subshell,there are $6$ electrons. According to Hund's rule,the dis

Vedclass · Accepted Answer

$49$

Vedclass · Answer

(B) The electronic configuration of $Fe$ $(Z = 26)$ is $[Ar] 3d^6 4s^2$.In the $3d$ subshell,there are $6$ electrons. According to Hund's rule,the distribution is:						$\uparrow \downarrow$			$\uparrow$			$\uparrow$			$\uparrow$			$\uparrow$			Number of unpaired electrons $(n) = 4$.The spin-only magnetic moment $(\mu)$ is given by the formula $\mu = \sqrt{n(n + 2)} \,BM$.$\mu = \sqrt{4(4 + 2)} = \sqrt{24} \,BM$.Using $\sqrt{24} \approx 4.899 \,BM$.$\mu = 48.99 	imes 10^{-1} \,BM$.Rounding off to the nearest integer,we get $49$.

In the ground state of atomic $Fe \,(Z = 26)$,the spin-only magnetic moment is ...... $\times 10^{-1} \,BM$. (Round off to the nearest integer).
$[$Given $: \sqrt{3} = 1.73, \sqrt{2} = 1.41]$

Similar Questions

What is the difference between $2p_x, 2p_y,$ and $2p_z$ orbitals?

Which one of the following electronic arrangements is absurd?

For a magnetic quantum number $m = 0, \pm 1$,the value of the principal orbital (azimuthal quantum number $l$) corresponds to which subshell,and what is the minimum principal quantum number $n$ required for this set?

Calculate the total number of angular nodes and radial nodes present in $3p$ orbital.

What is the maximum number of electrons that can be associated with the following set of quantum numbers?
$n = 3, l = 1$ and $m = -1$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In the ground state of atomic $Fe \,(Z = 26)$,the spin-only magnetic moment is ...... $\times 10^{-1} \,BM$. (Round off to the nearest integer).$[$Given $: \sqrt{3} = 1.73, \sqrt{2} = 1.41]$