In the $Hofmann$ bromamide degradation reaction,the number of moles of $NaOH$ and $Br_2$ used per mole of amine produced are:
- A$Two$ moles of $NaOH$ and $two$ moles of $Br_2$.
- B$Four$ moles of $NaOH$ and $one$ mole of $Br_2$.
- C$One$ mole of $NaOH$ and $one$ mole of $Br_2$.
- D$Four$ moles of $NaOH$ and $two$ moles of $Br_2$.
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