In the hydrogen atom,the electron is making 6 | vedclass

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(B) The equivalent current $i$ produced by the revolving electron is given by $i = q 
u,$ where $q$ is the charge of the electron $(1.6 	imes 10^{-1

Vedclass · Accepted Answer

$12.5$

Vedclass · Answer

(B) The equivalent current $i$ produced by the revolving electron is given by $i = q 
u,$ where $q$ is the charge of the electron $(1.6 	imes 10^{-19} \, C)$ and $
u$ is the frequency $(6.6 	imes 10^{15} \, r.p.s.)$.The magnetic field $B$ at the centre of a circular current loop is given by $B = \frac{\mu_0 i}{2r}$.Substituting $i = q 
u$ into the formula,we get $B = \frac{\mu_0 q 
u}{2r}$.Given $\mu_0 = 4\pi 	imes 10^{-7} \, T \cdot m/A$,$q = 1.6 	imes 10^{-19} \, C$,$
u = 6.6 	imes 10^{15} \, Hz$,and $r = 0.53 	imes 10^{-10} \, m$:$B = \frac{4\pi 	imes 10^{-7} 	imes 1.6 	imes 10^{-19} 	imes 6.6 	imes 10^{15}}{2 	imes 0.53 	imes 10^{-10}}$$B = \frac{2\pi 	imes 1.6 	imes 6.6 	imes 10^{-11}}{0.53 	imes 10^{-10}} \approx \frac{66.35}{5.3} \approx 12.518 \, T$.

In the hydrogen atom,the electron is making $6.6 \times 10^{15} \, r.p.s.$ If the radius of the orbit is $0.53 \times 10^{-10} \, m,$ then the magnetic field produced at the centre of the orbit is (in $Tesla$):

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