In the logic circuit given below, if X=1 and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given inputs are $X=1$ and $Y=1$.$1$. The input $X$ passes through a $NOT$ gate, so the input to the $OR$ gate is $\bar{X} = 0$.$2$. The input $Y$

Vedclass · Accepted Answer

$P=1, Q=1, R=0$

Vedclass · Answer

(A) Given inputs are $X=1$ and $Y=1$.$1$. The input $X$ passes through a $NOT$ gate, so the input to the $OR$ gate is $\bar{X} = 0$.$2$. The input $Y$ is directly connected to the $OR$ gate, so the input is $1$.$3$. The output $P$ of the $OR$ gate is $P = \bar{X} + Y = 0 + 1 = 1$.$4$. The input $X$ is directly connected to the $NAND$ gate, so the input is $1$.$5$. The input $Y$ passes through a $NOT$ gate, so the input to the $NAND$ gate is $\bar{Y} = 0$.$6$. The output $Q$ of the $NAND$ gate is $Q = \overline{X \cdot \bar{Y}} = \overline{1 \cdot 0} = \overline{0} = 1$.$7$. Finally, $P$ and $Q$ are inputs to a $NOR$ gate to give output $R$.$8$. $R = \overline{P + Q} = \overline{1 + 1} = \overline{1} = 0$.Thus, $P=1, Q=1, R=0$.

In the logic circuit given below, if $X=1$ and $Y=1$, then the values of $P, Q$ and $R$ are:

Similar Questions

Boolean algebra is essentially based on

The truth table given below is for which gate?
$A: 0, 0, 1, 1$
$B: 0, 1, 0, 1$
$C: 1, 1, 1, 0$

The output $Y$ of the given network is :-

In the following logic circuit,the sequence of the inputs $A, B$ are $(0, 0), (0, 1).$ The output $Y$ for this sequence will be

The output of the following combination is the same as that of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module