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(A) In the photoelectric effect, the intensity of incident light is directly proportional to the number of photons incident per unit area per unit tim

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the photoelectric current increases.

Vedclass · Answer

(A) In the photoelectric effect, the intensity of incident light is directly proportional to the number of photons incident per unit area per unit time. Since each photon ejects one photoelectron (provided the frequency is above the threshold frequency), increasing the intensity increases the number of photoelectrons emitted per second. Consequently, the photoelectric current increases. The kinetic energy of the emitted photoelectrons depends only on the frequency of the incident radiation and the work function of the metal, not on the intensity of the light. Therefore, the correct option is $A$.

In the photoelectric effect, keeping the frequency of incident radiation and the accelerating potential fixed, if the intensity of incident light is increased,

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