In the preparation of compounds of Xe,Bartlet | vedclass

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Question

(C) Bartlett observed that the first ionisation enthalpy of $Xe$ $(1170 \ kJ \ mol^{-1})$ is very close to that of the $O_2$ molecule $(1175 \ kJ \ mo

Vedclass · Accepted Answer

Both $O_2$ and $Xe$ have almost same ionisation enthalpy

Vedclass · Answer

(C) Bartlett observed that the first ionisation enthalpy of $Xe$ $(1170 \ kJ \ mol^{-1})$ is very close to that of the $O_2$ molecule $(1175 \ kJ \ mol^{-1})$.He used this similarity to predict that $PtF_6$ would also oxidise $Xe$ to $Xe^+$,similar to how it oxidises $O_2$ to $O_2^+$.Hence,option $C$ is correct.

In the preparation of compounds of $Xe$,Bartlett had taken $O_2^+PtF_6^-$ as a base compound. This is because:

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