In the presence of light,chloroform is slowly oxidised by air to form:

Match the $CH_{3}X$ compounds in Column-$(I)$ with their $C-X$ bond length in Column-$(II)$ and dipole moment in Column-$(III)$.

$(I)$ Compound	$(II)$ $C-X$ Bond Length $(pm)$	$(III)$ Dipole Moment $(D)$
$(A)$ $H_3C-F$	$(i)$ $214$	$(1)$ $1.636$
$(B)$ $H_3C-Cl$	$(ii)$ $193$	$(2)$ $1.830$
$(C)$ $H_3C-Br$	$(iii)$ $178$	$(3)$ $1.847$
$(D)$ $H_3C-I$	$(iv)$ $139$	$(4)$ $1.860$

The major product obtained in the following reaction is $C_2H_5ONa + (CH_3)_3C-Cl \rightarrow$

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

Predict the order of reactivity of the following compounds in $S_N1$ reaction.
$(I)$ $C_6H_5-CH_2Br$
$(II)$ $C_6H_5-CH(C_6H_5)Br$
$(III)$ $C_6H_5-CH(CH_3)Br$
$(IV)$ $C_6H_5-C(CH_3)(C_6H_5)Br$

What is the product formed by the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$?