In the reaction Me-C equiv C-Et xrightarrow{N | vedclass

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(B) $1$. The reduction of $Me-C \equiv C-Et$ with $Na/liq. NH_3$ (Birch reduction/dissolving metal reduction) yields the trans-alkene,$trans-pent-2-en

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$A$ binary mixture which is optically inactive due to external compensation

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(B) $1$. The reduction of $Me-C \equiv C-Et$ with $Na/liq. NH_3$ (Birch reduction/dissolving metal reduction) yields the trans-alkene,$trans-pent-2-ene$ $(P)$.$2$. The subsequent reaction of $trans-pent-2-ene$ with $Br_2$ in $CCl_4$ proceeds via anti-addition.$3$. Anti-addition of $Br_2$ to a trans-alkene results in the formation of a pair of enantiomers,which constitutes a racemic mixture.$4$. $A$ racemic mixture is optically inactive due to external compensation,as the optical rotation of one enantiomer is cancelled by the equal and opposite rotation of the other.

In the reaction $Me-C \equiv C-Et$ $\xrightarrow{Na/liq. NH_3} P$ $\xrightarrow[CCl_4]{Br_2} (Q)$; then $Q$ is

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