In the nuclear reaction _1^2H + _1^3H to _2^4 | vedclass

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Question

(B) The energy released in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy

Vedclass · Accepted Answer

$c - a - b$

Vedclass · Answer

(B) The energy released in a nuclear reaction is given by the difference between the total binding energy of the products and the total binding energy of the reactants.In the given reaction: $_1^2H + _1^3H 	o _2^4He + _0^1n$.The binding energy of the neutron $_0^1n$ is $0 \ MeV$.The total binding energy of the reactants is $a + b$.The total binding energy of the products is $c + 0 = c$.Therefore, the energy released $Q = (	ext{Total Binding Energy of Products}) - (	ext{Total Binding Energy of Reactants})$.$Q = c - (a + b) = c - a - b \ MeV$.

In the nuclear reaction $_1^2H + _1^3H \to _2^4He + _0^1n$, if the binding energies of $_1^2H$, $_1^3H$, and $_2^4He$ are respectively $a$, $b$, and $c$ (in $MeV$), then the energy (in $MeV$) released in this reaction is:

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