In the reaction given below,the product would | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction of but$-2-$ene with $H_3O^{+}$ involves the formation of a planar carbocation intermediate,$CH_3-CH_2-C^{+}H-CH_3$. Since the carboca

Vedclass · Accepted Answer

a racemic mixture

Vedclass · Answer

(D) The reaction of but$-2-$ene with $H_3O^{+}$ involves the formation of a planar carbocation intermediate,$CH_3-CH_2-C^{+}H-CH_3$. Since the carbocation is planar,the nucleophile $(H_2O)$ can attack from either side of the plane with equal probability. This results in the formation of a $50:50$ mixture of $(R)$ and $(S)$ enantiomers of butan$-2-$ol,which is a racemic mixture.

In the reaction given below,the product would be: $CH_3-CH=CH-CH_3 \xrightarrow{H_3O^{+}} CH_3-CH_2-CH(OH)-CH_3$

Similar Questions

Propene on hydroboration and oxidation produces

Which intermediate is formed when $HCl$ is added to propene in the presence of peroxide?

The product of the following reaction will be:

Predict the major alkene product formed upon heating the following ester:

The major product $(P)$ formed in the reaction below is: $HC \equiv C-CH_2-CH=CH_2 \xrightarrow[CCl_4, 253 \ K]{Br_2(1 \ mol)} P$

Vedclass Test Series

Exam Paper Generator

Online Exam Module