In the reaction with HCl,an alkene reacts in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Markovnikov's rule states that in the addition of a protic acid to an asymmetric alkene,the acid hydrogen attaches to the carbon with the smaller

Vedclass · Accepted Answer

Both $(A)$ and $(B)$

Vedclass · Answer

(C) Markovnikov's rule states that in the addition of a protic acid to an asymmetric alkene,the acid hydrogen attaches to the carbon with the smaller number of hydrogen atoms and the halide group attaches to the carbon with the larger number of hydrogen atoms. However,the product $1-$chloro$-1-$methylcyclohexane can be formed from both methylenecyclohexane and $1-$methylcyclohexene.For methylenecyclohexane: The protonation of the double bond leads to a $3^{\circ}$ carbocation at the $1-$position,which then reacts with $Cl^-$ to give $1-$chloro$-1-$methylcyclohexane.For $1-$methylcyclohexene: The protonation leads to a $2^{\circ}$ carbocation,which undergoes rearrangement to form a more stable $3^{\circ}$ carbocation,which then reacts with $Cl^-$ to give $1-$chloro$-1-$methylcyclohexane.Since both alkenes yield the same product,the correct answer is $(C)$.

In the reaction with $HCl$,an alkene reacts in accordance with the Markovnikov's rule to give a product $1-$chloro$-1-$methylcyclohexane. The possible alkene is

Similar Questions

Addition of $HCl$ does not obey Anti-Markovnikov's rule because

An optically active compound having molecular formula $C_8H_{16}$ on ozonolysis gives acetone as one of the products. The structure of the compound is

Addition of $HCl$ to propene in the presence of peroxides gives:

What is the product of the reaction: ${H_2}C = CH{(CH_2)_6}CH_3 \xrightarrow[peroxide]{HBr} ?$

$CH_3-CH=CH_2 + HBr \xrightarrow{\ \ } .........$,the product formed is

Vedclass Test Series

Exam Paper Generator

Online Exam Module