In the structure of SF_{4},the lone pair of e | vedclass

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(A) The central atom $S$ in $SF_{4}$ has $5$ electron pairs ($4$ bond pairs and $1$ lone pair),resulting in $sp^{3}d$ hybridization.According to $VSEP

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equatorial position and there are two lone pair-bond pair repulsions at $90^{\circ}$

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(A) The central atom $S$ in $SF_{4}$ has $5$ electron pairs ($4$ bond pairs and $1$ lone pair),resulting in $sp^{3}d$ hybridization.According to $VSEPR$ theory,the lone pair occupies the equatorial position in a trigonal bipyramidal geometry to minimize repulsion.In the equatorial position,the lone pair experiences repulsion from two axial bond pairs at $90^{\circ}$ and two equatorial bond pairs at $120^{\circ}$.Therefore,there are two lone pair-bond pair repulsions at $90^{\circ}$.

List-$I$	List-$II$
$A. XeF_4$	$I. See-saw$
$B. SF_4$	$II. Square planar$
$C. NH_4^{+}$	$III. Bent T-shaped$
$D. BrF_3$	$IV. Tetrahedral$

In the structure of $SF_{4}$,the lone pair of electrons on $S$ is in ....

Similar Questions

The number of lone pairs of electrons on the central atom of $XeO_3$, $XeOF_4$ and $XeF_6$ respectively is

Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. XeF_4$ $I. See-saw$
$B. SF_4$ $II. Square planar$
$C. NH_4^{+}$ $III. Bent T-shaped$
$D. BrF_3$ $IV. Tetrahedral$

Choose the correct answer from the options given below:

Among the compounds shown below,which one reveals a linear structure?

In which of the following options,the molecules are correctly arranged in the increasing order of their bond angles?

Which of the following is not tetrahedral?

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