The number of lone pairs of electrons on the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The central atom in all these compounds is Xenon $(Xe)$, which has $8$ valence electrons.$1$. In $XeO_3$: $Xe$ forms $3$ double bonds with $3$ oxy

Vedclass · Accepted Answer

$1, 1, 1$

Vedclass · Answer

(A) The central atom in all these compounds is Xenon $(Xe)$, which has $8$ valence electrons.$1$. In $XeO_3$: $Xe$ forms $3$ double bonds with $3$ oxygen atoms. It uses $6$ electrons for bonding. Remaining electrons = $8 - 6 = 2$. Thus, $1$ lone pair.$2$. In $XeOF_4$: $Xe$ forms $4$ single bonds with $4$ fluorine atoms and $1$ double bond with $1$ oxygen atom. It uses $4 + 2 = 6$ electrons for bonding. Remaining electrons = $8 - 6 = 2$. Thus, $1$ lone pair.$3$. In $XeF_6$: $Xe$ forms $6$ single bonds with $6$ fluorine atoms. It uses $6$ electrons for bonding. Remaining electrons = $8 - 6 = 2$. Thus, $1$ lone pair.Therefore, the number of lone pairs is $1, 1, 1$.

The number of lone pairs of electrons on the central atom of $XeO_3$, $XeOF_4$ and $XeF_6$ respectively is

Similar Questions

Decreasing order of bond angle is

In which of the following options,the molecules are correctly arranged in the increasing order of their bond angles?

The compound$(s)$ with $2$ lone pairs of electrons on the central atom is(are):
$(A)$ $BrF_5$
$(B)$ $ClF_3$
$(C)$ $XeF_4$
$(D)$ $SF_4$

The correct statement regarding the number of lone pairs on the central atoms of the molecules $SF_4$,$CF_4$,and $XeF_4$ is:

Which set of species is arranged in order of increasing $O-N-O$ bond angle?

Vedclass Test Series

Exam Paper Generator

Online Exam Module