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(C) The fringe width $\beta$ in Young's double slit experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength

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(C) The fringe width $\beta$ in Young's double slit experiment is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the screen and the slits,and $d$ is the distance between the two slits.From the relation $\beta \propto \lambda$,it is clear that the fringe width is directly proportional to the wavelength of the light used.Among the given colours,the wavelength of red light is the longest and the wavelength of blue light is the shortest.Since blue light has the shortest wavelength,the fringe width will be the least for blue light.

In the Young's double slit experiment,for which colour is the fringe width the least?

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