In what ratio should tea at ₹ 240 per kg be m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given:Selling Price $(S.P)$ of the mixture = ₹ $324$ per $kg$Profit percentage = $20 \%$Step $1$: Calculate the Cost Price $(C.P)$ of the mixture.

Vedclass · Accepted Answer

$1:3$

Vedclass · Answer

(C) Given:Selling Price $(S.P)$ of the mixture = ₹ $324$ per $kg$Profit percentage = $20 \%$Step $1$: Calculate the Cost Price $(C.P)$ of the mixture.$C.P = \frac{S.P 	imes 100}{100 + 	ext{Profit } \%}$$C.P = \frac{324 	imes 100}{120} = \frac{3240}{12} = ₹ 270$ per $kg$Step $2$: Apply the Alligation method.Cost of first type of tea = ₹ $240$ per $kg$Cost of second type of tea = ₹ $280$ per $kg$Mean price of mixture = ₹ $270$ per $kg$Using the rule of alligation:Ratio = $(280 - 270) : (270 - 240)$Ratio = $10 : 30$Ratio = $1 : 3$Therefore,the tea should be mixed in the ratio $1:3$.

In what ratio should tea at ₹ $240$ per $kg$ be mixed with tea at ₹ $280$ per $kg$ so that on selling the mixture at ₹ $324$ per $kg$ there is a profit of $20 \%$?

Similar Questions

In what ratio should wheat at ₹ $32$ per $kg$ be mixed with wheat at ₹ $24$ per $kg$ so that on selling the mixture at ₹ $39$ per $kg$,there is a profit of $30 \%$?

Mira's expenditure and savings are in the ratio $3: 2$. Her income increases by $10 \%$. Her expenditure also increases by $12 \%$. By how many $\%$ does her saving increase?

How many $kg$ of sugar costing ₹ $5.75$ per $kg$ should be mixed with $75 \, kg$ of cheaper sugar costing ₹ $4.50$ per $kg$,so that the mixture is worth ₹ $5.50$ per $kg$?

The ratio of milk and water in mixtures of four containers are $5:3, 2:1, 3:2$ and $7:4$ respectively. In which container is the quantity of milk,relative to water,minimum?

In what ratio must a grocer mix two varieties of tea worth ₹ $60$ a $kg$ and ₹ $65$ a $kg$ so that by selling the mixture at ₹ $68.20$ a $kg$ he may gain $10 \%$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module