In which of the following arrangements is the | vedclass

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(B) Let us analyze each option:$A$: $Al^{3+}, Mg^{2+}, Na^{+}, F^{-}$ are isoelectronic species with $10$ electrons. For isoelectronic species,ionic s

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$B < C < N < O$ $(1^{st} 	ext{ IP})$

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(B) Let us analyze each option:$A$: $Al^{3+}, Mg^{2+}, Na^{+}, F^{-}$ are isoelectronic species with $10$ electrons. For isoelectronic species,ionic size increases as the nuclear charge $(Z)$ decreases. The order $Al^{3+} (Z=13) $B$: The first ionization potential $(IP)$ generally increases across a period. However,$N$ has a stable half-filled $p$-orbital $(2p^3)$,so its $IP$ is higher than $O$. The correct order is $B $C$: Electron affinity $(EA)$ generally increases across a period,but $Cl$ has a higher $EA$ than $F$ due to the small size and inter-electronic repulsion in $F$. The order $I $D$: Metallic character increases down a group as ionization energy decreases. The order $Li < Na < K < Rb$ is correct.

In which of the following arrangements is the order $NOT$ according to the property indicated in the bracket?

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