In which of the following arrangements,the or | vedclass

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(C) The correct increasing order of basic strength for group $15$ hydrides is: $NH_3 > PH_3 > AsH_3 > SbH_3$. $NH_3$ is the most basic because of its

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$NH_3 < PH_3 < AsH_3 < SbH_3$ (basic strength)

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(C) The correct increasing order of basic strength for group $15$ hydrides is: $NH_3 > PH_3 > AsH_3 > SbH_3$. $NH_3$ is the most basic because of its small size,where the electron density of the lone pair is concentrated over a small region. As the size of the central atom increases,the electron density gets diffused over a larger surface area,decreasing the ability to donate the electron pair. Thus,the arrangement in option $C$ is incorrect. Option $A$ is correct as oxidising power increases down the group due to the inert pair effect. Option $B$ is correct as acidic strength increases with the increase in bond length down the group. Option $D$ is correct based on the electronic configuration and stability of half-filled $p$-orbitals in $N$.

In which of the following arrangements,the order is not strictly according to the property written against it?

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