In which of the following compounds is the ox | vedclass

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(B) To find the oxidation number of $C$,let it be $x$:$1.$ For $HCHO$: $x + 1(+1) + 1(-2) + 1(+1) = 0 \implies x + 2 - 2 = 0 \implies x = 0$.$2.$ For

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$CHCl_3$

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(B) To find the oxidation number of $C$,let it be $x$:$1.$ For $HCHO$: $x + 1(+1) + 1(-2) + 1(+1) = 0 \implies x + 2 - 2 = 0 \implies x = 0$.$2.$ For $CHCl_3$: $x + 1(+1) + 3(-1) = 0 \implies x + 1 - 3 = 0 \implies x = +2$.$3.$ For $CH_3OH$: $x + 3(+1) + 1(-2) + 1(+1) = 0 \implies x + 3 - 2 + 1 = 0 \implies x = -2$.$4.$ For $C_{12}H_{22}O_{11}$: $12x + 22(+1) + 11(-2) = 0 \implies 12x + 22 - 22 = 0 \implies 12x = 0 \implies x = 0$.Comparing the values,the maximum oxidation number is $+2$ in $CHCl_3$.

In which of the following compounds is the oxidation number of carbon maximum?

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