In which of the following molecules,the maxim | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} 	imes (V - N)$,where $V$ is the nu

Vedclass · Accepted Answer

$XeF_2$

Vedclass · Answer

(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} 	imes (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of electrons involved in bonding (monovalent atoms).$1$. For $NH_3$: Central atom $N$ has $5$ valence electrons. It forms $3$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (5 - 3) = 1$.$2$. For $H_2O$: Central atom $O$ has $6$ valence electrons. It forms $2$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (6 - 2) = 2$.$3$. For $ClF_3$: Central atom $Cl$ has $7$ valence electrons. It forms $3$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (7 - 3) = 2$.$4$. For $XeF_2$: Central atom $Xe$ has $8$ valence electrons. It forms $2$ bonds. $	ext{Lone pairs} = \frac{1}{2} 	imes (8 - 2) = 3$.Thus,$XeF_2$ has the maximum number of lone pairs $(3)$ on the central atom.

In which of the following molecules,the maximum number of lone pairs is present on the central atom?

Similar Questions

The shape of $IF_7$ molecule is

Which of the following represents the correct Lewis structure for the cyanate ion $(OCN^-)$?

The sets of molecules in which the central atom has no lone pair of electrons are:
$i$. $SnCl_2, NH_3, SF_4$
$ii$. $HgCl_2, SO_3, SF_6$
$iii$. $BeCl_2, BF_3, PCl_5$
$iv$. $ClF_3, BrF_5, XeF_6$

$BeCl_2$ is not isostructural with

What is the bond angle in $ClO_2$ (OClO) (in $^{\circ}$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module