In which of the following reactions does the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Oxymercuration-Demercuration $(OMDM)$ reaction involves the addition of $H_2O$ according to Markovnikov's rule without any carbocation rearrangeme

Vedclass · Accepted Answer

$CH_3-C(Ph)(CH_3)-CH=CH_2 \xrightarrow[2. NaBH_4]{1. Hg(OAc)_2/H_2O} 	ext{product}$

Vedclass · Answer

(B) Oxymercuration-Demercuration $(OMDM)$ reaction involves the addition of $H_2O$ according to Markovnikov's rule without any carbocation rearrangement.The reaction uses $Hg(OAc)_2/H_2O$ followed by reduction with $NaBH_4$.In contrast,acid-catalyzed hydration (options $a$ and $d$) involves a carbocation intermediate which can undergo rearrangement to form a more stable carbocation.Hydroboration-oxidation (option $c$) follows Anti-Markovnikov's rule.

In which of the following reactions does the addition of $H_2O$ take place according to Markovnikov's rule but without rearrangement?

Similar Questions

What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$

Preparation of alcohols from alkenes involves the electrophilic attack on alkene carbon. Explain its mechanism.

Heating of $2-$chloro$-1-$phenylbutane with $EtOK/EtOH$ gives $X$ as the major product. Reaction of $X$ with $Hg(OAc)_2/H_2O$ followed by $NaBH_4$ gives $Y$ as the major product. $Y$ is

From which of the following is tertiary butyl alcohol obtained by the action of methyl magnesium iodide?

Vedclass Test Series

Exam Paper Generator

Online Exam Module